date | time | site | canister | tare | wet | dry | density (g/cm^3) | moist (%V) | EC-5 reading (%V) | Qualitative Observations |
---|---|---|---|---|---|---|---|---|---|---|
10/2 | 1150 | beans | 1 | 21.2 | 115.0 | 99.0 | 1.17 | 24.1 | 22.9 | |
10/2 | 1638 | corn | 2 | 21.2 | 135.7 | 113.3 | 1.39 | 33.7 | 25.2 | |
10/2 | 1648 | grass | 3 | 21.3 | 126.2 | 108.8 | 1.32 | 26.2 | 16.5 | |
10/7 | 1605 | beans | 2 | 21.3 | 113.2 | 89.2 | 1.34 | 36.1 | 38.3 (strange waveform) | |
10/7 | 1525 | corn | 4 | 21.3 | 112.8 | 88.1 | 1.33 | 37.2 | 39.5 | |
10/7 | 1543 | grass | 3 | 21.4 | 109.2 | 82.4 | 1.24 | 40.3 | 29.8 | |
10/22 | 1358 | beans | 3 | 13.8 | 116.5 | 95.9 | 1.44 | 31.0 | 22.0 | Dark, minimal organic, significant clay content |
10/22 | 1451 | corn | 1 | 13.5 | 116.1 | 92.6 | 1.39 | 35.4 | 24.0 | Milk chocolate brown, small pieces of organic material, slightly sandy with large grains, clumpy/significant clay |
10/22 | 1428 | grass | 2 | 13.7 | 106.9 | 88.5 | 1.33 | 27.7 | 20.5 | Balanced brown, thick woody Grass Roots running throughout, clumpy with significant clay |
tare = c(21.2, 21.2, 21.3)
wet = c(115.0, 135.7, 126.2) - tare
dry = c(99.0, 113.3, 108.8) - tare
vol = c(3)*pi*(5.31/2)^2 # = 66.44 cm^3
moist = 100*(wet-dry)/vol
rho = dry/vol
1 Comment
Unknown User (gilmer)
I think the 10/2 density and moisture-by-volume calculations are slightly off. given a volume of 66.4cm^3, I calculate the 10/2 beans density=1.49g/cm3 and MBV=24.08%. Should I update the table?