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Date/TimeLocationTare (g)Wet (g)Dry (g)Density (g/cm^3)Qsoil (cm^3/cm^3) %EC5 Reading (cm^3/cm^3) %Diff (cm^3/cm^3) %
20 Feb 2015/1157bao, 2--5cm5.58100.7483.541.1725.8923.981.9
20 Feb 2015/1112bao, 10--13cm2.1599.5987.361.2818.4116.382.0
20 Feb 2015/1129bao, 20-23cm2.5089.5178.511.1416.5613.173.4
9 Mar 2015/1430ehs, 2--5cm16.477152142.333127.7411.673721.029628.4-6.4
20 Apr 2015/1500ehs,4--7cm8.237+8.26081.960+60.946  73.235+53.0561.8225.01 29.47-4.5
20 Apr 2015/1500ehs, 9--12cm8.232+8.21471.380+74.505  62.691+66.1091.9125.72 28.20-2.5
20 Apr 2015/1500

ehs

, 19--22cm

, 19–22cm

(not completely full, by about 2mm?)

8.265+2.13996.082+29.133  85.418+25.465

1.63

(likely low)

21.57 26.00-4.4

 

Note: Dry taken 23 Feb after air-drying in the lab for 3 days, then baking in the toaster oven for an hour.  (The oven got rid of about another 1.5g in each sample.)

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Note5: 20 Apr EC5 readings taken using minicom – see teardown comment.

Note6: assume that 9 Mar had a math error: 142.333, rather than 152.333???

 

tare = c(5.58, 2.15, 2.50, 16.477,8 8.237+8.260,8 8.232+8.214,8 8.265+2.139)

wet = c(100.74, 99.59, 89.51, 152142.333,81 81.960+60.946,71 71.380+74.505,96 96.082+29.133)-tare

dry = c(83.54, 87.36, 78.51, 127.741, 73.235+53.056, 62.691+66.109, 85.418+25.465)-tare

vol = 3*pi*(5.31/2)^2

rho = dry/vol

moist = (100*(wet-dry)/vol) # density numerically equal to volume mixing ratio since rho_water = 1.

ec5 = c(23.98, 16.38, 13.17, 28.4, 29.47, 28.20, 26.00)

matplot(moist,ec5,xlim=c(0,40),ylim=c(0,40)); abline(0,1,lty=2)

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